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In addition to solving the port problem of A, the serial number problem also needs to be paid attention to. The serial number corresponds to the sliding window. The fake TCP packet needs to be filled with the serial number. If the value of the serial number is not in the sliding window of B when it is sent to B before A, B will actively discard it. So we need to find the serial number that can fall into the sliding window between AB at that time. This can be solved violently, because the length of a sequence is 32 bits, and the value range is 0-4294967296. If the window size is like 65535 under Windows I caught in the above figure, I only need to divide, and I know that at most I only need to send 65537 (4294967296/65535=65537) packets to have a sequence number fall into the sliding window. The desired value can be calculated quickly by exhaustion on multiple control hosts.就算把这身老骨头丢在眉山，也不叫你们白跑这一趟。大王，一路辛劳，还是先进城再说吧。　　四十年过去了，血浓于水的亲情召唤让他们挣脱命运再次团聚在一起，尽管人事全非，他们依然找回了那份不可取代的亲情与挚爱。Large packets exceed the maximum transmission unit (MTU) of Ethernet, which can force the target to fragment and reorganize when receiving UDP data, causing network congestion. . . .[Traffic] Take 803, 5 and 14 to Quanzhou Forest Park Station.System.out.println ("Modified status:" + origi.getValue ());